x^2+14x+22=0

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Solution for x^2+14x+22=0 equation:


Simplifying
x2 + 14x + 22 = 0

Reorder the terms:
22 + 14x + x2 = 0

Solving
22 + 14x + x2 = 0

Solving for variable 'x'.

Begin completing the square.

Move the constant term to the right:

Add '-22' to each side of the equation.
22 + 14x + -22 + x2 = 0 + -22

Reorder the terms:
22 + -22 + 14x + x2 = 0 + -22

Combine like terms: 22 + -22 = 0
0 + 14x + x2 = 0 + -22
14x + x2 = 0 + -22

Combine like terms: 0 + -22 = -22
14x + x2 = -22

The x term is 14x.  Take half its coefficient (7).
Square it (49) and add it to both sides.

Add '49' to each side of the equation.
14x + 49 + x2 = -22 + 49

Reorder the terms:
49 + 14x + x2 = -22 + 49

Combine like terms: -22 + 49 = 27
49 + 14x + x2 = 27

Factor a perfect square on the left side:
(x + 7)(x + 7) = 27

Calculate the square root of the right side: 5.196152423

Break this problem into two subproblems by setting 
(x + 7) equal to 5.196152423 and -5.196152423.

Subproblem 1

x + 7 = 5.196152423 Simplifying x + 7 = 5.196152423 Reorder the terms: 7 + x = 5.196152423 Solving 7 + x = 5.196152423 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = 5.196152423 + -7 Combine like terms: 7 + -7 = 0 0 + x = 5.196152423 + -7 x = 5.196152423 + -7 Combine like terms: 5.196152423 + -7 = -1.803847577 x = -1.803847577 Simplifying x = -1.803847577

Subproblem 2

x + 7 = -5.196152423 Simplifying x + 7 = -5.196152423 Reorder the terms: 7 + x = -5.196152423 Solving 7 + x = -5.196152423 Solving for variable 'x'. Move all terms containing x to the left, all other terms to the right. Add '-7' to each side of the equation. 7 + -7 + x = -5.196152423 + -7 Combine like terms: 7 + -7 = 0 0 + x = -5.196152423 + -7 x = -5.196152423 + -7 Combine like terms: -5.196152423 + -7 = -12.196152423 x = -12.196152423 Simplifying x = -12.196152423

Solution

The solution to the problem is based on the solutions from the subproblems. x = {-1.803847577, -12.196152423}

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